Math

The length of a rectangle is 2 more than 3 times its width. Find the dimensions of the rectangle if the perimeter is 44 in.

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1. L = 3W + 2

2L + 2W = 2(3W+2) + 2W = 44

Solve for W then L.

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2. Let w = the width
Let 3w + 2 = the length
P = 2l + 2w
44 = 2(3w+2) + 2w
44 = 6w + 4 + 2w
44 = 8w + 4
40 = 8w
w = 5 feet
length - 3w + 2 = 3(5) + 2 = 15 + 2
l = 17 feet

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