Math

The length of a rectangle is 2 more than 3 times its width. Find the dimensions of the rectangle if the perimeter is 44 in.

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  1. L = 3W + 2

    2L + 2W = 2(3W+2) + 2W = 44

    Solve for W then L.

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  2. Let w = the width
    Let 3w + 2 = the length
    P = 2l + 2w
    44 = 2(3w+2) + 2w
    44 = 6w + 4 + 2w
    44 = 8w + 4
    40 = 8w
    w = 5 feet
    length - 3w + 2 = 3(5) + 2 = 15 + 2
    l = 17 feet

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