arah Meeham blends coffee for​ Tasti-Delight. She needs to prepare 120 pounds of blended coffee beans selling for ​$ 4.75 per pound. She plans to do this by blending together a​ high-quality bean costing ​$ 5.25per pound and a cheaper bean at ​$ 3.25 per pound. To the nearest​ pound, find how much​ high-quality coffee bean and how much cheaper coffee bean she should blend.

h + c = 120 ... 13 h + 13 c = 13 * 120

5.25 h + 3.25 c = 4.75 * 120
... dividing by .25 ... 21 h + 13 c = 19 * 120

subtracting equations ... 8 h = 6 * 120

solve for h , then substitute back to find c

If using x lbs of cheaper coffee, then

3.25x + 5.25(120-x) = 4.75*120
x=30, so
30 lbs cheap, 90 lbs expensive

makes sense, since 4.75 is much closer to 5.25 than it is to 3.25

To find how much high-quality coffee bean and cheaper coffee bean Sarah should blend, we can set up a system of equations.

Let's assume she needs to blend x pounds of high-quality coffee bean and y pounds of cheaper coffee bean.

According to the problem, she needs to prepare a total of 120 pounds of blended coffee beans. Therefore, we can write the first equation as:

x + y = 120

Next, we know that the blended coffee beans will sell for $4.75 per pound. The cost of the high-quality coffee bean is $5.25 per pound, and the cheaper coffee bean is $3.25 per pound. So, the second equation can be written as:

(5.25 * x) + (3.25 * y) = 4.75 * 120

Now, we can solve this system of equations.

First, multiply the first equation by 3.25 to eliminate y:

3.25x + 3.25y = 3.25 * 120

Next, subtract the above equation from the second equation:

(5.25 * x) + (3.25 * y) - (3.25x + 3.25y) = 4.75 * 120 - 3.25 * 120

This simplifies to:

5.25x - 3.25x = 570 - 390

2x = 180

Divide both sides by 2:

x = 90

Now, substitute this value of x into the first equation to find y:

90 + y = 120

y = 120 - 90

y = 30

Therefore, Sarah should blend 90 pounds of high-quality coffee bean and 30 pounds of cheaper coffee bean.

To summarize, Sarah should blend 90 pounds of high-quality coffee bean with 30 pounds of cheaper coffee bean to prepare 120 pounds of blended coffee beans.