College Precal Algrebra

Perform the operation and write the result in standard form.
(√19 + √20i)(√19 – √20i)

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  3. 👁 34
  1. 19 - 20i

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  2. @OOF I tried that. It's saying that it's wrong

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  3. i reworked it a bunch of times and i'm stumped. i'm sorry

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  4. since (a+b)(a-b) = a^2-b^2
    (√19 + √20i)(√19 – √20i)
    = 19 - 20i^2 = 19+20 = 39

    (a-bi)(a+bi) = a^2+b^2

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    oobleck

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