A solution of hydrogen peroxide is 15.2% by mass what is the molarity of the solution. Assume that the solution has a density of 1.01g/ml
Ah, hydrogen peroxide, the magical potion of cleanliness! Now, let's tackle your question. First, we need to convert the given mass percentage to molarity. To do that, we need to calculate the mass of hydrogen peroxide in the solution.
Since the density is given, we can determine the volume of the solution. Assuming that a milliliter (ml) is equivalent to a cubic centimeter (cm^3), we know that the density is 1.01 g/ml. Therefore, the mass of the solution occupying 100 ml (or 100 cm^3) would be 100 g.
Now, the same percentage by mass can be applied to this new mass. So, 15.2% of 100 g is 15.2 g.
The molarity of a solution is defined as the number of moles of solute per liter of solution. To calculate this, we need to know the molar mass of hydrogen peroxide (H2O2), which is approximately 34.02 g/mol.
We can now calculate the number of moles of hydrogen peroxide present in the solution by dividing the mass of hydrogen peroxide (15.2 g) by its molar mass (34.02 g/mol). The result is approximately 0.447 mol.
Finally, we can determine the molarity by dividing the number of moles of solute by the volume of the solution in liters. Since 100 ml is equivalent to 0.1 liters, we divide 0.447 mol by 0.1 liters and find that the molarity of the solution is approximately 4.47 M.
So, in conclusion, the molarity of the solution is about 4.47 M. But hey, don't you dare drink it, unless you want to become Clowntenstein! Stay safe!
To find the molarity of the solution, we need to first calculate the mass of hydrogen peroxide present in 1 liter of the solution.
Given that the solution is 15.2% by mass, this means that 100 g of the solution contains 15.2 g of hydrogen peroxide.
We can convert this to grams of hydrogen peroxide in 1 liter (1000 mL) of the solution by using the density:
15.2 g / 100 g * 1000 mL = 152 g
Now we need to calculate the molarity of the solution. The formula to calculate molarity is:
Molarity (M) = moles of solute / volume of solution in liters
To determine the moles of solute (hydrogen peroxide), we need to use the molar mass of hydrogen peroxide, which is 34.02 g/mol.
Moles of hydrogen peroxide = mass / molar mass
Moles of hydrogen peroxide = 152 g / 34.02 g/mol ≈ 4.47 mol
Finally, we need to divide the moles of hydrogen peroxide by the volume of the solution in liters:
Molarity = 4.47 mol / 1 L = 4.47 M
Therefore, the molarity of the solution is approximately 4.47 M.
To find the molarity of the solution, we need to know the concentration in terms of moles of solute per liter of solution. In this case, the solute is hydrogen peroxide (H2O2).
First, let's determine the mass of the solute in the solution. The solution is 15.2% by mass, which means that 100 g of the solution contains 15.2 g of H2O2.
Next, we need to convert the mass of H2O2 to moles. The molar mass of H2O2 is 34.0147 g/mol.
Number of moles of H2O2 = (mass of H2O2) / (molar mass of H2O2)
= 15.2 g / 34.0147 g/mol
Now, let's find the volume of the solution in liters. The density of the solution is given as 1.01 g/mL.
Volume of the solution = (mass of the solution) / (density of the solution)
= 100 g / 1.01 g/mL
Since 1 mL is equal to 1 cm³ and 1 L is equal to 1000 cm³, we can convert the volume to liters.
Volume of the solution = (100 g / 1.01 g/mL) / 1000 (in liters)
Now, we have the moles of H2O2 and the volume of the solution in liters, so we can calculate the molarity using the equation:
Molarity (M) = (moles of solute) / (volume of solution in liters)
Substituting the values:
Molarity (M) = [(15.2 g / 34.0147 g/mol) / (100 g / 1.01 g/mL) / 1000]
After performing the calculations, the result will give you the molarity of the solution.