The larger of two numbers is 10 less than twice the smaller number. If the sum of the two numbers is 38, find the two numbers.
uhh whats this website for then? i thought yall were supposed to help. tf yall saying and I'm asking HOW to do it, yall making it seem like I'm asking just for the answers.
Looks to be that oobleck showed you HOW to do it just fine.
To find the two numbers, let's assign variables to represent them. Let's call the smaller number "x" and the larger number "y".
According to the problem, the larger number is 10 less than twice the smaller number. Mathematically, we can express this as:
y = 2x - 10
We are also given that the sum of the two numbers is 38. Mathematically, we can express this as:
x + y = 38
Now we have a system of two equations:
y = 2x - 10
x + y = 38
We can solve this system of equations using the substitution method or the elimination method. Let's use the substitution method in this case.
1. Solve the first equation, y = 2x - 10, for y.
We get y = 2x - 10.
2. Substitute this expression for y into the second equation, x + y = 38.
Replace y with 2x - 10:
x + (2x - 10) = 38.
3. Simplify and solve for x:
3x - 10 = 38.
3x = 48.
x = 16.
4. Now that we have the value of x, substitute it back into one of the original equations to find y.
Let's use the first equation, y = 2x - 10.
Substitute x = 16:
y = 2(16) - 10 = 22.
Therefore, the two numbers are x = 16 and y = 22.
didn't we just do one like this for you?
x + (2x-10) = 38
Now finish it off