calculus

write the vertex form equation of each parabola.

1) Vertex:(-5,8), Focus:(-21/4, 8)
2) Vertex:(-6,-9), Directrix: x= 47/8
3)Vertex(8,-1) y- intercept: -17
4) Open left or right, Vertex: (7, 6), passes through:(-11,9)
5)Focus(-63/8, -7), Directrix: x= -65/8
6 Opens up or down, and passes through (−6, −7), (−11, −2), and (−8, 1)
7) Vertex at origin, opens left, 1/8units between the vertex and focus.
8) Vertex: (10, 0), axis of symmetry: y = 0,
length of latus rectum = 1, a < 0

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  1. I am supposed to do all your homework for you?

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    Damon
  2. it suppose to be a homework help page no?

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  3. Try and you will get help if stuck.

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    Damon
  4. It is a help page. Things work better if you show you are willing to make some effort.

    To get you started, the parabola
    y^2 = 4px has
    vertex at (0,0)
    focus at (0,p)
    directrix is the line x = -p
    latus rectum has length 4p

    So, for
    5)Focus(-63/8, -7), Directrix: x= -65/8
    The distance between focus and directrix is 2p, so 2p = 1/4, p = 1/8
    Since the directrix is a vertical line, the axis is horizontal
    Since the focus is at y = -7, that is the axis
    The vertex is at (-64/8,-7) = (-8,-7)
    So the equation is
    (y+7)^2 = 1/2 (x+8)
    See the graph and properties at

    https://www.wolframalpha.com/input/?i=parabola+%28y%2B7%29%5E2+%3D+1%2F2+%28x%2B8%29

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    oobleck

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