PLS HELP
A projectile is fired from the origin (at y = 0 m) as shown in the diagram above. The initial velocity components are Vx = 140 m/s and Vy = 84 m/s. The projectile reaches maximum height at point P, then it falls and strikes the ground at point Q, which is 20 m below the launch point. Assuming air resistance is negligible, what is the horizontal component of the velocity (Vx) of the projectile at point P?
the horizontal speed remains constant at 140 m/s
gravity only acts downward
To find the horizontal component of the velocity (Vx) of the projectile at point P, we can use the concept of projectile motion.
In projectile motion, the horizontal and vertical components of motion are independent of each other. This means that the horizontal component of velocity remains constant throughout the entire motion of the projectile.
Given that the initial horizontal velocity component (Vx) is 140 m/s, we can conclude that the horizontal component of the velocity at point P is also 140 m/s.
Therefore, the horizontal component of the velocity (Vx) of the projectile at point P is 140 m/s.