AA × AA = BOB,
A^A= A × A,
PP × PP = PAP. If each letter in the given equations stands for a number between 1 to 9, what is PP × AA?
A*A = A^2, so A=2
22*22 = 484
11*11 = 121
11*22 = 242 = ABA
Thanks
best answer
To find the values of the letters in the equation, we need to solve them one by one using the given equations.
Let's start with the equation A^A = A × A. Since any number raised to the power of 1 is itself, we can conclude that A must be equal to 1.
Next, we can substitute the value of A in the equation AA × AA = BOB. This gives us 11 × 11 = BOB. After performing the multiplication, we have 121 = BOB.
Similarly, substituting the value of A in the equation PP × PP = PAP, we get PP × PP = P1P. Since the same digit multiplied by itself gives a number with the same digit in the middle, we can conclude that P must be equal to 1.
Now we have the values: A = 1, B = 2, and P = 1.
To find PP × AA, we substitute the values of P and A into the equation:
PP × AA = 11 × 11 = 121.
So, PP × AA equals 121.