Write each in Standard Form and Slope-Intercept Form:
4x = 2y -10
I consider 4x - 2y = -10 as standard form, of course why not reduce it to
2x - y = -5
slope-yintercept form: y = 2x+5
To write the equation 4x = 2y - 10 in standard form, we need to move all the variables to one side of the equation and have the constant term on the other side.
Starting with 4x = 2y - 10, let's subtract 2y from both sides:
4x - 2y = -10
Now, to write the equation in slope-intercept form, we need to solve for y. Let's isolate y by subtracting 4x from both sides:
-2y = -4x - 10
Next, divide both sides by -2 to make y alone:
y = 2x + 5
Therefore, the equation 4x = 2y - 10 can be written in standard form as 4x - 2y = -10, and in slope-intercept form as y = 2x + 5.
To write the equation in standard form, we need to rearrange the equation so that all the variables are on the left side and the constant term is on the right side.
Let's start by moving the term with the variable y to the left side:
4x + 10 = 2y
Next, let's divide both sides of the equation by 2 to simplify it:
(4/2)x + 10/2 = (2/2)y
This gives us:
2x + 5 = y
So, the equation in standard form is: 2x - y = -5
To write the equation in slope-intercept form, we need to isolate y on one side.
Starting with our equation in standard form, 2x - y = -5, we can subtract 2x from both sides:
-y = -2x - 5
Next, let's multiply both sides by -1 to get y on its own:
y = 2x + 5
So, the equation in slope-intercept form is: y = 2x + 5.