A baseball pitcher throws a pitch, and the batter hits it at a 45 ̊ angle. It just clears the outfield fence 98m away. The fence is the same height as the pitch.
a.Find the velocity of the ball when it left the bat
b.Find the amount of time the ball stayed in the air
the range equation is ... d = v^2 * sin(2Θ) / g
... d is the distance (range) ... 98 m
... v is the launch velocity
... Θ is the launch angle ... 45º
... g is gravitational acceleration ... 9.81 m/s^2
... in this special case , launch and landing height are the same
a. plug in the given quantities and solve the equation for v
b. find the vertical component of v to find the flight time (to the fence)
... without the launch and fence height, the exact flight time is unknown