# TCS Placement: Sample Questions 265 - 267 of 502

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## Question 265

### Explanation

Program:

`#include<stdio.h>`

`int main()`

`{`

`int x=15, y=20;`

`x=x+y;`

`y=x-y;`

`x=x-y;`

`printf(“After swapping :x=%d, y=%d”, x, y);`

`return 0;`

`}`

- Output:

After swapping: x = 20, y = 15

## Question 266

### Question

MCQ▾A is 20 percent more efficient than B. If two persons can complete a piece of work in 60 days then in how many days A working alone can complete the work?

### Choices

Choice (4) | |
---|---|

a. | 90 |

b. | 100 |

c. | 80 |

d. | 110 |

### Answer

d.### Explanation

- A is 20 % more efficient than B.
- If B՚s per day work is 100 units then A՚s per day work will be 120.
- Both persons together complete a day.
- If they work together, they will take 60 days to complete the work. So total work = 60 x 220
- We are asked to find the number of days to complete the work when A alone is working, which will be
- So, A alone will take 110 days to complete the work.

## Question 267

### Question

MCQ▾If a man can swim downstream at 6kmph and upstream at 2kmph, his speed in still water is:

### Choices

Choice (4) | |
---|---|

a. | 4kmph |

b. | 2kmph |

c. | 2.5kmph |

d. | 3kmph |

### Answer

a.### Explanation

- Let the speed of man in still water is u kmph.
- Downstream speed means person is swimming in the direction of water and upstream speed means person is swimming in the opposite direction of flowing water.
- Downstream speed, a = 6 kmph and upstream speed, b = 2 kmph
- Speed of man, u = (a + b) /2

u = (6 + 2) /2

u = 4 kmph

- Man՚s speed will be 4 kmph in still water.