What is the value of f(2) for f(x)=2x5−8x4+3x3−4x2+9x−1?
can i get a step by step on this? my final answer was like -1000000 range lmfao
sorry that formatted wrong, there is an exponent at the end of each thing. for instance, 2x^5, 8x^4 and so on. not for 1 tho
ok, so you want
f(x)=2x^5−8x^4+3x^3−4x^2+9x−1
then f(2) = 2(2^5) - 8(2^4) + 3(2^3) - 4(2^2) + 9(2) - 1
= 2(32) - 8(16) + 3(8) - 4(4) + 18 - 1
= ..... finish it please
a final answer of of around -1000000 makes no sense at all
To find the value of f(2) for the given function f(x), you need to substitute x with 2 in the function expression and evaluate it. Let's break down the steps:
Step 1: Start with the given function, f(x) = 2x^5 - 8x^4 + 3x^3 - 4x^2 + 9x - 1.
Step 2: Substitute x with 2 in the function expression:
f(2) = 2(2)^5 - 8(2)^4 + 3(2)^3 - 4(2)^2 + 9(2) - 1.
Step 3: Simplify the calculation within parentheses:
f(2) = 2(32) - 8(16) + 3(8) - 4(4) + 9(2) - 1.
Step 4: Perform the calculations:
f(2) = 64 - 128 + 24 - 16 + 18 - 1.
Step 5: Continue simplifying:
f(2) = -63.
Hence, the value of f(2) is -63.