A 0.25kg block of pure material is heated from 20 degree Celsius to 65 degree Celsius by the addition of 4.35 killer Jules of energy . Calculate the specific heat and identify the substance it is most likely composed
45º temperature change
SH = heat / (mass * temperature change) = 4.35 kJ / [.25 kg * (65 - 20)ºC]
To calculate the specific heat of the substance, we can use the formula:
Q = mcΔT
where:
Q is the amount of energy transferred (in joules)
m is the mass of the substance (in kilograms)
c is the specific heat capacity of the substance (in J/kg·°C)
ΔT is the change in temperature (in °C)
In this case, we are given:
Q = 4.35 kJ = 4.35 × 10^3 J
m = 0.25 kg
ΔT = 65°C - 20°C = 45°C
Plugging in these values into the formula, we get:
4.35 × 10^3 J = 0.25 kg × c × 45°C
Now, we can solve for c:
c = (4.35 × 10^3 J) / (0.25 kg × 45°C)
c ≈ 96.67 J/kg·°C
Therefore, the specific heat of the substance is approximately 96.67 J/kg·°C.
To identify the substance, we can compare its specific heat capacity to known values for different materials. The specific heat values of common substances are usually provided in reference tables. By comparing the calculated specific heat value of 96.67 J/kg·°C to the values in the table, we can determine the substance it is most likely composed of.