a spring 20cm long is stretched to 40cm by a load of 50n .what is
1.the length when stretched by 100n
2.what is the work done when stretched by 100n
1. twice the force, so twice the stretch
2. F = kx, so k = 50N/20cm = 2.5 N/cm
W = 1/2 kx^2
1.the length when stretched by 100n
2.what is the work done when stretched by 100n
2. F = kx, so k = 50N/20cm = 2.5 N/cm
W = 1/2 kx^2