y - 7 = 3(x + 2)
I need to graph in slope intercept form.
y = 3x+13
Now graph as usual.
y = 3x + 6 + 7
y = 3x + 13
well, you know one point is (0,13), the y-intercept
another nice one is (-4,1)
now graph the line
To graph the equation y - 7 = 3(x + 2) in slope-intercept form (y = mx + b), you need to isolate y on one side of the equation. Let's solve for y:
Step 1: Distribute the 3 to the terms inside the parentheses: y - 7 = 3x + 6.
Step 2: Move the constant term (-7) to the other side of the equation by adding 7 to both sides: y = 3x + 6 + 7.
Step 3: Simplify: y = 3x + 13.
Now that the equation is in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, you can identify the slope and y-intercept.
The slope (m) is the coefficient of x, so in this case, the slope is 3.
The y-intercept (b) is the constant term, which is 13 in this case.
So, the slope-intercept form of the equation is y = 3x + 13.
To graph this equation, start by plotting the y-intercept, which is (0, 13). Then, using the slope of 3, you can find additional points by moving three units up and one unit to the right from the y-intercept, which gives you the point (1, 16). You can continue this process to plot more points, or you can draw a straight line that passes through these two points.