How many grams of Na2O are required to produce 160 grams of NaOH?
what was the answer?
124
I got 247.92
I got 248
To determine the number of grams of Na₂O required to produce 160 grams of NaOH, we need to use the molar ratios from the balanced chemical equation. The balanced chemical equation for the reaction between Na₂O and NaOH is:
Na₂O + H₂O -> 2NaOH
From the equation, we can see that 1 mole of Na₂O reacts to produce 2 moles of NaOH.
To calculate the number of moles of NaOH produced from 160 grams, we divide the given mass by the molar mass of NaOH. The molar mass of NaOH is the sum of the atomic masses of its constituent elements: sodium (Na), oxygen (O), and hydrogen (H).
Molar mass of NaOH = 23 g/mol (Na) + 16 g/mol (O) + 1 g/mol (H) = 40 g/mol
Moles of NaOH = Mass of NaOH / Molar mass of NaOH = 160 g / 40 g/mol = 4 moles
Since the molar ratio of Na₂O to NaOH is 1:2, we need half as many moles of Na₂O as moles of NaOH. Therefore, we require:
Moles of Na₂O = 1/2 * Moles of NaOH = 1/2 * 4 moles = 2 moles
Finally, to convert moles of Na₂O to grams, we multiply the moles by the molar mass of Na₂O. The molar mass of Na₂O is the sum of the atomic masses of sodium (Na) and oxygen (O).
Molar mass of Na₂O = 23 g/mol (Na) + 16 g/mol (O) + 16 g/mol (O) = 62 g/mol
Grams of Na₂O = Moles of Na₂O * Molar mass of Na₂O = 2 moles * 62 g/mol = 124 grams
Therefore, 124 grams of Na₂O are required to produce 160 grams of NaOH.