How much more is the rate of change of function 2 than the rate of change of function 1? Function 2 y = 5x + 4
Function 1 y=3
well, y=3 is constant, so it does not change.
now, what is the slope of F2? (y = mx+b)
To find the rate of change for each function, we need to find the slope of their graphs. The slope represents how much the function is changing for each unit change in the x-coordinate.
For Function 2: y = 5x + 4, the rate of change is represented by the coefficient of x, which is 5. This means that for every increase of 1 in the x-coordinate, the y-coordinate will increase by 5.
For Function 1: y = 3, the rate of change is 0 since the equation does not contain an x-term. This means that the y-coordinate remains constant regardless of the value of x.
Therefore, the rate of change for Function 2 is 5, while the rate of change for Function 1 is 0. The rate of change for Function 2 is greater than the rate of change for Function 1 by 5 units.
To find the rate of change of a function, you need to determine the slope of the function.
Function 2: y = 5x + 4
The slope of this function (or rate of change) is the coefficient of x, which is 5. So, the rate of change for Function 2 is 5.
Function 1: y = 3
In this case, since there is no x term, the slope (or rate of change) is 0. This means that Function 1 has no change in the y-axis for any change in the x-axis.
To compare the rate of change between Function 2 and Function 1, you subtract the rate of change of Function 1 from the rate of change of Function 2:
Rate of change of Function 2 - Rate of change of Function 1 = 5 - 0 = 5
Therefore, the rate of change of Function 2 is 5 more than the rate of change of Function 1.