In parallelogram EFGH, let M be the midpoint of side EF, and let N be the midpoint of side EH. Line segments FH and GM intersect at P, and line segments FH and GN intersect at Q. Find PQ/FH.

To find the ratio PQ/FH in parallelogram EFGH, we can use properties of parallel lines and midpoints.

Let's start by identifying the relationship between the line segments FH, GM, GN, and PQ. Since GM and GN are both diagonals in parallelogram EFGH, they bisect each other, which means they intersect at their common midpoint O. Therefore, we can label point O as the intersection of GM and GN.

Now, let's examine the triangle FHN. From the given information, we know that M and N are the midpoints of EF and EH, respectively. Since M and N are midpoints, we can conclude that FM = ME and NE = EH. Furthermore, we know that FH is parallel to GM and GN because they are opposite sides of a parallelogram.

Using these observations, we can apply the midpoint theorem to triangle FHN. According to the midpoint theorem, when a line segment connects the midpoints of two sides of a triangle, it is parallel to and half the length of the third side. In this case, PQ is the line segment connecting the midpoints of FH and HN.

Therefore, we can establish the following relationships: PQ is parallel to FH and PQ is half the length of HN. Mathematically, we can express these relationships as PQ || FH and PQ = (1/2) × HN.

Now, let's examine the triangle FGH. Since PQ is parallel to FH, we can use the Intercept Theorem to establish the relationship between PQ, HG, and FH. According to the Intercept Theorem, if two or more parallel lines intercept transversals, they cut off proportional segments. In this case, PQ is the transversal intersecting FH, and GM || FH.

Applying the Intercept Theorem, we can conclude that PQ/FH = GN/HM. Since GN = GN (common side) and HM = EM (both are midsegments), we can substitute values to simplify the ratio. Thus, we have PQ/FH = GN/EM.

In summary, the ratio PQ/FH can be determined by finding the ratio of the lengths of the segments GN and EM. To obtain the values of GN and EM, additional lengths or measurements of the parallelogram EFGH would need to be provided.