Given that α is in Quadrant 1 and tan(α)=67, give an exact answer for the following:

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  1. is 67 a typo or is it really that close to the y axis?
    anyway find sin α and cos α from the tangent then
    given sin α / cos α = k (here k = 67)
    so sin α = k cos α
    sin 2α = 2 sin α cos α = 2 k cos^2 α
    cos 2α = cos^2 α - sin^2 α
    tan 2α = sin 2α / cos2α

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  2. Its a typo. It's suppose to be 6/7 .

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  3. well that seriously helps
    opposite/adjacent = 6/7
    then hypotenuse = sqrt (36 + 49) = sqrt 85
    so sin α = 6/sqrt 85
    and cos α = 7/sqrt85
    use those in the equations I gave you

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