An object weighs 0.25 N in air, 0. 18 when immersed in water and 0.20 N when immersed in oil. Calculate the density of the object and density of the oil

the object displaces 0.07 N of water and 0.05 N of oil

the density of the object is 25/7 times the density of water

the density of the oil is 5/7 times the density of water

To calculate the density of the object, we can use the equation:

density = mass / volume

However, we are not given the mass or volume directly. We are given the weight of the object in different fluids. We can use the concept of buoyant force to find the volume and mass of the object.

The weight of the object in the air is given as 0.25 N. Since the object is in equilibrium in air, its weight is equal to the force of gravity acting on it. Therefore, the weight of the object is equal to the mass of the object multiplied by the acceleration due to gravity.

Weight in air = mass * acceleration due to gravity

0.25 N = mass * 9.8 m/s^2

Solving for the mass of the object, we get:

mass = 0.25 N / 9.8 m/s^2

Now let's calculate the volume of the object when submerged in water. The weight of the object in water is given as 0.18 N. The object experiences an upward buoyant force equal to the weight of the fluid it displaces. Therefore, the weight of the object in water is equal to the buoyant force minus the weight of the object.

Weight in water = buoyant force - weight of object

0.18 N = buoyant force - 0.25 N

Solving for the buoyant force, we get:

buoyant force = 0.18 N + 0.25 N

Next, the buoyant force is equal to the weight of the water displaced, which is given by:

buoyant force = density of water * volume of object * acceleration due to gravity

Substituting the values and solving for the volume of the object, we get:

0.18 N + 0.25 N = density of water * volume of object * 9.8 m/s^2

Now, we can calculate the volume of the object when submerged in oil. The weight of the object in oil is given as 0.20 N. Using a similar approach, we can find the volume of the object when immersed in oil.

0.20 N + 0.25 N = density of oil * volume of object * 9.8 m/s^2

Now, we have two equations:

0.18 N + 0.25 N = density of water * volume of object * 9.8 m/s^2
0.20 N + 0.25 N = density of oil * volume of object * 9.8 m/s^2

By rearranging these equations, we can solve for the density of the object and the density of the oil. However, we need additional information such as the densities of water and oil.

To calculate the density of an object, you can use the formula:

Density = Mass / Volume

However, in this case, we do not have the values for the mass or volume of the object directly. We can still calculate the density using the information given.

Given the weights of the object in air, water, and oil, we can use the principle of Archimedes' buoyancy to find the volume of the object.

Archimedes' principle states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. In other words, the weight loss of an object when submerged in a fluid is equal to the weight of the fluid it displaces.

Let's find the volume of the object when completely submerged in water:

Weight in air = 0.25 N
Weight in water = 0.18 N

Weight loss = Weight in air - Weight in water
= 0.25 N - 0.18 N
= 0.07 N

Since weight loss is equal to the weight of the water displaced by the object, we can use the density of water to find the volume:

Density of water = 1000 kg/m^3 (approximate value)

Volume = Weight loss / Density of water
= 0.07 N / 1000 kg/m^3
= 0.00007 m^3

Now we have the volume of the object when submerged in water. We can use the weight loss when submerged in oil to find the density of the oil as well.

Weight in air = 0.25 N
Weight in oil = 0.20 N

Weight loss = Weight in air - Weight in oil
= 0.25 N - 0.20 N
= 0.05 N

Since weight loss is equal to the weight of the oil displaced by the object, we can use the volume we calculated earlier to find the density of the oil:

Density of oil = Weight loss / Volume
= 0.05 N / 0.00007 m^3
= 714.29 kg/m^3

Therefore, the density of the object is equal to the density of water which is approximately 1000 kg/m^3 and the density of the oil is approximately 714.29 kg/m^3.