a spinner has 8 equal sections
3 are red
4 are blue
and 1 is yellow
the spinner is spun twice
what is the probability of getting a red on the first spin and blue on the second?
is it
3/18
4/16
4/10
7/8
P*red,blue) = 3/8 * 4/8 = ____
I suspect a typo
joe mama
Don't even ask who Joe mama is (search the last part up on google)
To determine the probability of getting a red on the first spin and a blue on the second spin, you need to consider the total number of possible outcomes and the number of favorable outcomes.
The total number of possible outcomes for the first spin is 8 (since there are 8 equal sections on the spinner), and the total number of possible outcomes for the second spin is also 8.
For the first spin, there are 3 red sections out of 8 total sections, so the probability of getting a red on the first spin is 3/8.
For the second spin, there are 4 blue sections out of 8 total sections, so the probability of getting a blue on the second spin is 4/8, which simplifies to 1/2.
To find the probability of both events occurring (red on the first spin and blue on the second spin), you multiply the probabilities together: (3/8) * (1/2) = 3/16.
Therefore, the correct answer is 3/16.
So I am not good at explaining math, haha, but I can give you a really helpful video! Enter this link but delete the space between the "l" and the "a" at the very end of the link, and the space between the first two "w"s: www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:prob-comb/x9e81a4f98389efdf:combinatorics-precalc/v/permutation-formula
It's a video by Kahn Acadamy and was a life-saver when I was learning this.