Calculus

Multiply. √3/2cis(2π/9)·√6/4cis(3π/2). Which is the answer?


A)2√3/8cis(31π/18)
B)3√2/8cis(π/3)
C)3√2/8cis(31π/18)
D)2√3/8cis(π/3)

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  1. √3/2cis(2π/9)·√6/4cis(3π/2)
    = (√3/2)(√6/4) cis(2π/9 + 3π/2)
    = √18/8 cis (31π/18)
    = 3√2/8 cis 31π/18

    check my arithmetic

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