What is the magnitude of the potential different across the 5ohm resistor?
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The other resistors are equivalent to a 20Ω in parallel with a 30Ω, giving a
1/R = 1/20 + 1/30
R = 12Ω
So now you have a 5Ω and a 12Ω in series
5/17 * 11V = 3.24V
To determine the magnitude of the potential difference (V) across the 5ohm resistor, we need to use Ohm's Law. Ohm's Law states that the potential difference across a resistor (V) is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor.
In the given circuit diagram, if we assume that the current flowing through the 15ohm resistor is I1, and the current flowing through the 5ohm resistor is I2, then we can calculate the potential difference across the 5ohm resistor using the following steps:
1. Use Kirchoff's loop rule to write an equation for the potential difference across the 15ohm and 5ohm resistors.
- Start at the top left corner of the circuit and move in a loop clockwise.
- As you pass through the 15ohm resistor, you will experience a potential drop equal to 15ohm * I1.
- When you come to the 5ohm resistor, you will experience a potential drop equal to 5ohm * I2.
- The total potential difference across the circuit is equal to zero since it forms a closed loop.
2. Set up the equation:
- 15ohm * I1 - 5ohm * I2 = 0
3. Rearrange the equation:
- 15ohm * I1 = 5ohm * I2
4. Solve for I2:
- I2 = (15ohm * I1) / 5ohm = 3 * I1
5. Substitute the value of I2 into the equation for the potential difference across the 5ohm resistor:
- V = 5ohm * I2 = 5ohm * (3 * I1) = 15ohm * I1
Therefore, the magnitude of the potential difference across the 5ohm resistor is equal to 15 times the current flowing through the 15ohm resistor.
To determine the magnitude of the potential difference across the 5-ohm resistor, you first need to understand the circuit configuration and the available information.
Unfortunately, the image you provided is not accessible. Therefore, I cannot directly analyze the circuit and provide an answer. However, I can guide you through the general steps to calculate the potential difference in a circuit.
1. Identify the circuit configuration: Determine whether the circuit is a series or parallel configuration. This information helps you understand how the resistors are connected.
2. Apply Ohm's Law: Ohm's Law states that the potential difference (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R). Mathematically, V = I * R.
3. Calculate the current: Find the current flowing in the circuit. If you know the current or have information about the voltage source, you can use Kirchhoff's current law or apply basic circuit analysis techniques (such as using voltage dividers).
4. Use voltage division (if required): If the circuit is a series configuration and you have multiple resistors in the path, use the voltage division formula to calculate the potential difference across the 5-ohm resistor. The potential difference can be calculated using the following formula: V = (R2 / (R1 + R2)) * Vtotal, where R2 is the resistance of the 5-ohm resistor, R1 is the resistance of the other resistor(s) in series, and Vtotal is the total potential difference in the circuit.
5. Substitute the values: Once you have all the required values, plug them into the formulas and calculate the potential difference across the 5-ohm resistor.
Remember that without the specific circuit diagram or values, it is not possible to provide an accurate answer. Double-check the circuit configuration and use the provided equations to calculate the potential difference across the 5-ohm resistor in your specific circuit configuration.