The primary coil consists of 2 loops and there is a voltage of 6 V across the coil. If the secondary coil consists of 10 loops, what is the induced voltage?
30 V
11 V
3.3 V
6 V
30 V
the ratio of the voltages is the same as the ratio of the loops
The induced voltage in the secondary coil can be determined using the formula:
V_secondary = (N_secondary / N_primary) * V_primary
Where:
V_secondary = induced voltage in the secondary coil
N_secondary = number of loops in the secondary coil
N_primary = number of loops in the primary coil
V_primary = voltage across the primary coil
Given that the primary coil consists of 2 loops and there is a voltage of 6 V across the coil, and the secondary coil consists of 10 loops, we can substitute the values into the formula:
V_secondary = (10 / 2) * 6
V_secondary = 5 * 6
V_secondary = 30 V
Therefore, the induced voltage in the secondary coil is 30 V. So the correct answer is 30 V.
To find the induced voltage in the secondary coil, you can use the formula for voltage in a transformer:
V2 = (N2 / N1) * V1
where V2 is the induced voltage in the secondary coil, N2 is the number of loops in the secondary coil, N1 is the number of loops in the primary coil, and V1 is the voltage across the primary coil.
In this case, N2 = 10 (number of loops in the secondary coil), N1 = 2 (number of loops in the primary coil), and V1 = 6 V.
Plugging these values into the formula:
V2 = (10 / 2) * 6
V2 = 30 V
So, the induced voltage in the secondary coil is 30 V.
Therefore, the correct answer is 30 V.