What are the coefficients "a" and "b" of the Linear Least Mean Squares (LLMS) estimator in the equation VˆL = aU + b, given that V and U are independent random variables with zero means and variances of 1 and 2, respectively?

To find the coefficients "a" and "b" of the Linear Least Mean Squares (LLMS) estimator, we need to minimize the mean squared error between the estimated values VˆL and the true values V.

The LLMS estimator equation is given by:
VˆL = aU + b

Given that V and U are independent random variables with zero means and variances of 1 and 2, respectively, we can write the mean squared error as follows:

MSE (Mean Squared Error) = E[(V - VˆL)^2]

Expanding and rearranging the above equation, we have:

MSE = E[(V - (aU + b))^2]
= E[V^2 - 2aUV + (a^2U^2 + 2abU + b^2)]

Since V and U are independent, the cross-term 2aUV becomes zero. Also, since both V and U have zero mean, E[V^2] = 1 and E[U^2] = 2.

Furthermore, to minimize the mean squared error, we take partial derivatives of the MSE with respect to "a" and "b" and set them to zero. Solving these equations will provide the optimal values for "a" and "b" in the LLMS estimator.

Partial derivative with respect to "a":
dMSE/da = -2E[UV] + 2aE[U^2] + 2bE[U]
= -2E[UV] + 4a + 2bE[U]

Partial derivative with respect to "b":
dMSE/db = 2b - 2E[V]

Setting the partial derivatives to zero, we have:

-2E[UV] + 4a + 2bE[U] = 0
2b - 2E[V] = 0

Solving these two equations simultaneously will give us the optimal values for "a" and "b". Keep in mind that E[UV] and E[V] need to be calculated for your specific distribution of U and V.

To determine the coefficients "a" and "b" of the Linear Least Mean Squares (LLMS) estimator in the equation VˆL = aU + b, we can use the properties of independent random variables and the formula for LLMS.

Given:
- V and U are independent random variables.
- V has zero mean and a variance of 1.
- U has zero mean and a variance of 2.

In LLMS, the coefficients "a" and "b" are chosen to minimize the mean squared error between the estimated value VˆL and the true value V. The formula for the LLMS estimator is:

VˆL = aU + b

Since V and U are independent, the covariance between V and U is zero. Therefore, the cross-product term in the covariance calculation is eliminated:

Cov(V, U) = E[(V - E[V])(U - E[U])] = E[V * U] - E[V] * E[U] = E[V] * E[U] - E[V] * E[U] = 0

To find the value of "a," we can use the formula:

a = Cov(V, U) / Var(U)

Since Cov(V, U) is zero (as shown above) and Var(U) is given to be 2, we have:

a = 0 / 2 = 0

Therefore, the value of "a" is 0.

To find the value of "b," we can use the formula:

b = E[V] - a * E[U]

Since a is 0 and E[V] is 0 (given that V has a zero mean), we have:

b = 0 - 0 * E[U] = 0

Therefore, the value of "b" is also 0.

Hence, the coefficients "a" and "b" in the LLMS estimator are both 0, resulting in the equation:

VˆL = 0U + 0

or simply:

VˆL = 0