# Math

2r+3s=29
3r+2s=16
In elimination method

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1. 2r+3s=29...
3r+2s=16....

You have two choices eliminate r or s

I choose r

Multiply the first equation by 3
And the second by2

6r+9s=87.....(*)
9r+4s=32.....(**)

Subtract (**) from *

9s-4s=87-32

5s=55
s=11

To get r now from the very (*)

6r=87-9s

r=(87-9s)/6=?

Or
Assuming you want to do this all over again

This time eliminate s to get r what would you do??

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2. Correction
6r+9s=87...(*)
6r+4s=33...(**)

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3. Arrrrg
Correction again
6r+9s=87...(*)
6r+4s=32...(**)

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