Math

2r+3s=29
3r+2s=16
In elimination method

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  1. 2r+3s=29...
    3r+2s=16....

    You have two choices eliminate r or s

    I choose r

    Multiply the first equation by 3
    And the second by2

    6r+9s=87.....(*)
    9r+4s=32.....(**)

    Subtract (**) from *

    9s-4s=87-32

    5s=55
    s=11

    To get r now from the very (*)

    6r=87-9s

    r=(87-9s)/6=?

    Or
    Assuming you want to do this all over again

    This time eliminate s to get r what would you do??

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  2. Correction
    6r+9s=87...(*)
    6r+4s=33...(**)

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  3. Arrrrg
    Correction again
    6r+9s=87...(*)
    6r+4s=32...(**)

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