___3.0Ω__
| |
3.0Ω 3.0Ω
_____| |_____
|__3.0Ω__|
What is the equivalent resistance for the resistors in the figure shown above?
-1.3Ω
-2.2Ω*
-3.0Ω
-12.0Ω
please confirm :)
oops looks like that diagram didnt translate well, here
*******___3.0Ω__*******
*******|***********|*******
*****3.0Ω******3.0Ω****
_____|***********|_____
*******|__3.0Ω__|*******
ignore the asterisks. they are there for spacing
looks like 9 in parallel with 3
1 / r = (1 / 9) + (1 / 3)
multiplying by 9r ... 9 = r + 3 r
To find the equivalent resistance for the resistors in the given figure, we can use the concept of series and parallel resistors.
In this case, the resistors that are directly connected along a single path can be combined as:
- The two 3.0Ω resistors in series can be added together: 3.0Ω + 3.0Ω = 6.0Ω.
Now, we have a combination of three resistors, with two 6.0Ω resistors in parallel. To find the equivalent resistance, we can apply the formula:
1/Req = 1/R1 + 1/R2,
where Req is the equivalent resistance, and R1 and R2 are the resistances in parallel.
Let's calculate:
1/Req = 1/6.0Ω + 1/6.0Ω
1/Req = 2/6.0Ω
1/Req = 1/3.0
Therefore, Req = 3.0Ω.
So, the correct answer is -3.0Ω.