There is a bag with 10 marbles. There are 6 blue marbles and 4 red marbles. What is the probability of picking 2 red marbles without replacement?
its 4/10*3/9 = 2/5*1/3 = 2/15 ur welcome :)
there are 10C2 ways of picking two marbles
there are 4C2 ways of picking two red marbles
p(2 red) = 4C2 / 10C2
Probability of picking 2red without replacement=4/10×3/9=2/5×1/3=2/15
To calculate the probability of picking 2 red marbles without replacement from a bag with 10 marbles (6 blue and 4 red), we need to follow these steps:
Step 1: Find the total number of ways to pick 2 marbles from the bag without replacement.
To do this, we can use the combination formula. The number of ways to choose 2 marbles from 10 is calculated by: C(10, 2) = 10! / (2! * (10-2)!) = 45.
Step 2: Find the number of ways to pick 2 red marbles from the bag without replacement.
Since there are 4 red marbles in the bag, the number of ways to choose 2 red marbles from 4 is calculated by: C(4, 2) = 4! / (2! * (4-2)!) = 6.
Step 3: Calculate the probability by dividing the number of favorable outcomes (picking 2 red marbles) by the total number of possible outcomes.
Probability = Number of ways to pick 2 red marbles / Total number of ways to pick 2 marbles = 6/45 = 2/15.
Therefore, the probability of picking 2 red marbles without replacement from the given bag is 2/15.