how do I put -27x=-9y-45 in slope-intercept form?
9y+27x-45
divide both sides by 9:
Y = 3x-5.
1. the y term alone on the left
9y = 27x - 45
2. divide by the coefficient of the y term
y = (27/9)x - 45/9
y = 3x - 5
or
notice that each term divides by 9 , ---> -3x = -y - 5
rearrange to
y = 3x - 5
To put the equation -27x = -9y - 45 in slope-intercept form (y = mx + b), follow these steps:
Step 1: Start by isolating the y-term on one side of the equation. You can do this by adding 9y to both sides of the equation:
-27x + 9y = -45
Step 2: Rearrange the equation so that the y-term is on the left side and the x-term is on the right side:
9y = 27x - 45
Step 3: Divide both sides of the equation by 9 to isolate y:
y = (27/9)x - 45/9
Step 4: Simplify the equation:
y = 3x - 5
Therefore, the equation -27x = -9y - 45 can be written in slope-intercept form as y = 3x - 5.
To put the equation -27x = -9y - 45 in slope-intercept form, follow these steps:
Step 1: Move the terms with variables to one side:
-27x + 9y = -45
Step 2: Rearrange the equation to isolate y by moving the constant term to the other side:
9y = -27x - 45
Step 3: Divide all terms by the coefficient of y to get y alone on one side:
y = (-27/9)x - (45/9)
Step 4: Simplify the equation:
y = -3x - 5
So the equation -27x = -9y - 45 can be written in slope-intercept form as y = -3x - 5.
The slope-intercept form is y = mx + b, where m represents the slope of the line and b represents the y-intercept (the point where the line intersects the y-axis).