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Find the area of the complex figure.

A figure has 8 sides; all sides meet at right angles. The left-most vertical side measures 31 meters. The lower most horizontal side measures 69 meters. The right-most vertical side measures 31 meters. The upper right horizontal side measures 23 meters. The middle horizontal side measures 23 meters. The upper middle left vertical side measures 12 meters.

Can you help me solve this problem?

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  1. To find the area of this figure, there is two choices
    1. cut it into 3 rectangles.
    2.find the missing rectangle in the middle......

    find the missing area in the middle, 12* 23 = 276
    the area of the whole figure 31*69-276=1863m²

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  2. Thx broden

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  3. thank you @Reed that helped me out :3

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  4. i copied

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  5. IS that a minus symbol or a multiply

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  6. Help this sign here * is multiply!!!! for information

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  7. I know what to do. So we can divide the shape into three rectangles. There should be square and two rectangles. So for the rectangles we will find the lengths. We know that 31 is the total width of rectangle one and two, 12 is the other length but we need to the total length. So, 31 - 12 = 19. Since we have 19 that is going to be the width of our square. We have 23 as our length of the square 19 x 23 = 437. Then. we have 69 as the base of our shape. We can subtract 23 from 69, leaving us with 46. The equation to the area is 46 x 31 + 19 x 23, leaving us with an area of 1863, which is the area.

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