An electric water pump rated 1.5 kilowatt lifts 200kg of water through a vertical height of 6meter in 10seconds what is the efficiency of the pump
energy = m g h = 200 kg * 9.8 m/s^2 * 6 m = ? Joules
power = work / time = energy / 10 s = ? Watts
efficiency = power / 1.5 kw
To calculate the efficiency of the pump, we need to first determine the work done by the pump and the input power.
1. Calculate the work done by the pump:
The work done by the pump can be calculated using the formula: Work = Force x Distance.
In this case, the force is equal to the weight of the water being lifted, and the distance is the height through which the water is lifted.
Force = mass x gravity
Force = 200kg x 9.8m/s² (acceleration due to gravity)
Force = 1960 Newtons
Work = Force x Distance
Work = 1960 Newtons x 6 meters
Work = 11,760 Joules
2. Calculate the input power to the pump:
The input power is given as 1.5 kilowatts. To convert this to watts, we multiply by 1000.
Input power = 1.5 kilowatts x 1000
Input power = 1500 watts
3. Calculate the efficiency:
Efficiency = (Work output / Input power) x 100%
Plugging in the values we calculated:
Efficiency = (11,760 Joules / 1500 watts) x 100%
Efficiency = 7.84
Therefore, the efficiency of the pump is approximately 7.84%.
To calculate the efficiency of the electric water pump, we need to find the input power and the output power.
The input power is given by the formula:
Input Power = Output Power + Power Losses
The output power is the useful work done by the pump, which is given by the formula:
Output Power = Work Done / Time
1. Calculating the Work Done:
Work Done = Force × Distance
In this case, the force is equal to the weight of the water being lifted and the distance is the height the water is lifted.
Weight = mass × gravitational acceleration
The mass of the water is given as 200 kg, and the gravitational acceleration is approximately 9.8 m/s^2.
Weight = 200 kg × 9.8 m/s^2 = 1960 N
Work Done = Weight × Distance
Work Done = 1960 N × 6 m = 11760 joules (J)
2. Calculating the Output Power:
Output Power = Work Done / Time
Here, the work done is given as 11760 J and the time taken is given as 10 seconds.
Output Power = 11760 J / 10 s = 1176 watts (W)
3. Calculating the Input Power:
Input Power = Output Power + Power Losses
Since there is no additional information given about the power losses, we'll assume they are negligible.
Input Power = Output Power = 1176 W
4. Calculating the Efficiency:
Efficiency = (Output Power / Input Power) × 100%
Efficiency = (1176 W / 1500 W) × 100%
Efficiency = 78.4%
Therefore, the efficiency of the pump is approximately 78.4%.
F = M*g = 200*6 = 1200 N.
Po = F*d/T = 1200*6/10 = 720 J/s = 720 Watts = power out.
eff. = (Po/Pi) * 100% = (720/1500) * 100% = 48%.