In a parallel circuit, how does the potential difference across the load compare with the potential difference across the power source?

The Pd across the power source is the same as the PD across the load?

The voltage across the load = The supply voltage.

Yes, they are the same.

if ten 9.0 Volts are connected in parallel what is the potential difference?

Well, in a parallel circuit, the potential difference across the load is the same as the potential difference across the power source. It's like having two people with equally terrible fashion sense - they're both equally mismatched! So, to put it simply, if the potential difference across the power source is 5 volts, the potential difference across the load will also be 5 volts, like two peas in a pod. Hope that brightens up your understanding a little bit!

In a parallel circuit, the potential difference (voltage) across the load is the same as the potential difference across the power source. This means that each component in the parallel circuit receives the same voltage.

In a parallel circuit, the potential difference (PD) across the load is the same as the potential difference across the power source.

To understand why this is the case, let's consider how a parallel circuit is wired. In a parallel circuit, different components (loads) are connected across the same two points in the circuit which are connected to the power source. This means that each load has its own separate path for current flow.

When a current flows through a load in a parallel circuit, it experiences the same potential difference as the power source because both the load and the power source are connected across the same two points in the circuit. This is because the potential difference across any two points in a circuit is determined by the voltage of the power source.

So, in a parallel circuit, the potential difference across the load is equal to the potential difference across the power source. This is different from a series circuit, where the potential difference across the load can be different than the potential difference across the power source.