Solve for x.
x2 + 4x − 12 = 0
A) x = −4 or x = 3
B) x = 4 or x = −3
C) x = −6 or x = 2
D) x = 6 or x = −2
x = [ -4 +/- sqrt (16 + 48) ] / 2
= [ -4 +/- 8 ] /2
= [ -4 + 8 ] /2 or [ -4 - 8 ] / 2
x^2+4x-12 = 0. -12 = -2*6. -2+6 = 4 = B.
(x-2)(x+6) = 0
x-2 = 0. X = 2.
x+6 = 0. X =
@henry x=-6
To solve for x in the quadratic equation x^2 + 4x - 12 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a, b, and c are the coefficients of the quadratic equation. Comparing the given equation with the general form ax^2 + bx + c = 0, we find that a = 1, b = 4, and c = -12.
Now, substituting these values into the quadratic formula:
x = (-(4) ± √((4)^2 - 4(1)(-12))) / (2(1))
Simplifying further:
x = (-4 ± √(16 + 48)) / 2
x = (-4 ± √64) / 2
x = (-4 ± 8) / 2
Now, we have two possible values for x:
x = (-4 + 8) / 2 = 4 / 2 = 2
x = (-4 - 8) / 2 = -12 / 2 = -6
Therefore, the solutions for x are x = 2 and x = -6. So the correct answer is C) x = -6 or x = 2.