A spring of force constant 1500n/m is acted upon by a constant force of 75n.calculate the potential energy stored in the spring.

x = F/x

Pe = (1/2) k x^2

I mean x = F/k

To calculate the potential energy stored in a spring, you can use the formula:

Potential energy (U) = (1/2)kx^2

Where:
- U is the potential energy stored in the spring
- k is the force constant of the spring
- x is the displacement of the spring from its equilibrium position

In this case, we are given the force constant (k) as 1500 N/m. However, we need to determine the displacement (x) of the spring caused by the constant force of 75 N.

To find the displacement (x), we can use Hooke's Law, which states:

Force (F) = -kx

Rearranging the formula, we have:

x = -F/k

Substituting the given values, we get:

x = -75 N / 1500 N/m
x = -0.05 m

Since the displacement (x) is squared in the potential energy formula, we take the absolute value:

x^2 = (0.05 m)^2
x^2 = 0.0025 m^2

Now we can calculate the potential energy (U) using the formula:

U = (1/2)kx^2

Substituting the given values:

U = (1/2)(1500 N/m)(0.0025 m^2)
U = 1.875 J

Therefore, the potential energy stored in the spring is 1.875 joules.