What is the coefficient of x in the division (18^3+12x^2-3x)/6x^2
How do I solve this?
1. yea the answer is 3 or a
2. Factor the numerator and denominator and cancel the common factors x^2 - 12 or b
3. 2/a-1 or a
4. The expression is undefined where the denominator equals 0, the argument of an even indexed radical is less than 0, or the argument of a logarithm is less than or equals 0. b= -4 or d
5. (x+4)(x+5)/2 or b
6. 4/a or d
7. 9x + 31/x +4 or a
8. 0 or b
9. exact form x = 1/5 decimal form 0.2 or c
10. x = -6 or d
11. 15/2x or c
12. 2 hours or c
well,
(18x^3+12x^2-3x)/6x^2 = 3x + 2 - 1/2x
so, ...
I'm so confused...
3x +2 - 1/2 = 3x + 1.5.
coefficient of X = 3.
I<3rats you just saved my life! ilysm
To find the coefficient of x in the given division, you need to perform polynomial long division. Here's how you can solve it step by step:
Step 1: Write the division in the standard form with the dividend (numerator) on top and the divisor (denominator) on the bottom:
(18^3+12x^2-3x) divided by 6x^2
Step 2: Divide the first term of the dividend by the first term of the divisor. In this case, divide (18^3) by (6x^2) to get 3x.
Write the result (3x) above the division bar.
3x
-------------
6x^2 | 18^3+12x^2-3x
Step 3: Multiply the divisor (6x^2) by the result obtained in the previous step (3x). In this case, multiply (6x^2) by (3x) to get 18x^3. Write this under the dividend.
3x
-------------
6x^2 | 18^3+12x^2-3x
-18x^3
Step 4: Subtract the obtained product (18x^3) from the dividend term directly above it (12x^2) and write the resulting polynomial under the line.
3x
-------------
6x^2 | 18^3+12x^2-3x
-18x^3
_______
12x^2
Step 5: Divide the first term of the new dividend term (12x^2) by the first term of the divisor (6x^2) to get 2.
Write the result (2) above the division bar next to the previously obtained term.
3x + 2
-------------
6x^2 | 18^3+12x^2-3x
-18x^3
_______
12x^2
Step 6: Multiply the divisor (6x^2) by the result obtained in the current step (2). In this case, multiply (6x^2) by (2) to get 12x^2. Write this under the line.
3x + 2
-------------
6x^2 | 18^3+12x^2-3x
-18x^3
12x^2
_______
0
Step 7: Since the remainder term is zero and there are no more terms to divide, the division process is complete.
Finally, the coefficient of x in the division (18^3+12x^2-3x)/6x^2 is 3 in 3x + 2.