An engine has an efficiency of 60%. If the heat source inputs
26,000 J of heat energy every second, show why the engine
does 15,600 J of work every second.
I really have no clue how to do this question.
the energy in is 26,000 Joules/second
the energy(work) out is x Joules per second
energy out per second = efficiency * energy in per second
x = 0.60 * 26,000
x = 15,600 Joules per second (which is Watts by the way)
To solve this question, you need to understand the concept of efficiency and how work is calculated. Let's break it down step by step:
1. Efficiency: Efficiency is a measure of how effectively a machine or system converts input energy into useful output energy. In this case, the engine is said to have an efficiency of 60%. This means that 60% of the heat energy input into the engine is converted into useful work, while the remaining 40% is lost as waste heat.
2. Calculation of Work: Work is calculated using the formula: Work = Input Energy - Wasted Energy. In this case, the input energy is the heat energy provided to the engine, which is 26,000 J every second. The wasted energy is the energy lost as waste heat, which is 40% of the input energy, or 40% of 26,000 J.
Now, let's calculate the work done by the engine every second:
Step 1: Calculate the wasted energy:
Wasted Energy = 40% of 26,000 J
= (40/100) * 26,000 J
= 10,400 J
Step 2: Calculate the work done:
Work = Input Energy - Wasted Energy
= 26,000 J - 10,400 J
= 15,600 J
Therefore, the engine does 15,600 J of work every second.
I hope this explanation helps you understand the process of solving this problem.