Math

PLEASE HELP I REALLY NEED IT!!

A rectangular box is 8 inches in length, 3 inches in width, and 5 inches in height.

The figure shows a rectangular box of length 8 inches, width 3 inches, and height 5 inches. The diagonal of this rectangular box is the hypotenuse of a right triangle and the height of the rectangular box is the height of the triangle.

Suppose the three-dimensional diagonal is also the hypotenuse of a right triangle. If a vertical edge is one of the legs of that right triangle, what is the length of the second leg? Round your answer to the nearest tenth of an inch. Show all of your work.
Determine the length of the three-dimensional diagonal. Round your answer to the nearest tenth of an inch. Show all of your work.

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  1. The "second leg" of the right-angled triangle is the diagonal of the base of the box
    let that length be x
    x^2 = 8^2 + 3^ = 73

    Let the length of the 3-D diagonal be d
    d^2 = x^2 + 5^2
    = 73 + 25 = ...

    I will let you finish this

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    Reiny
  2. I am confused this is the question
    The volume of a rectangular prism is 288 cubic inches. The length of the rectangular prism is 0.36 inches and the width is 8 inches. What is the height of the rectangular prism?

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