In a restaurant 13% customers rated the food as 'poor', 22% of the customer rated the food as 'satisfactory' and 65% rated it as 'good'.A random sample of 12 customers who went for a meal at restaurant was taken.On a separate occasion, a random sample of n customers who went for a meal at the restaurant was taken.Find the smallest value of n for which the probability that at least 1 person will rate the food as 'poor' is greater than 0.95.

Solve it by using log
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To solve this problem using logarithms, we'll need to find the smallest value of n for which the probability that at least one person will rate the food as 'poor' is greater than 0.95.

Let's first calculate the probability that a single customer rates the food as 'poor'. We know that 13% of customers rated the food as 'poor', so the probability of a single customer rating it as 'poor' is 0.13.

The probability that a single customer does not rate the food as 'poor' is equal to 1 minus the probability that they do rate it as 'poor'. Therefore, the probability that a single customer does not rate the food as 'poor' is 1 - 0.13 = 0.87.

Now, let's consider the probability that none of the n customers rate the food as 'poor'. Since the samples are taken randomly, the probability that a single customer does not rate the food as 'poor' applies to all n customers. Therefore, the probability that none of the n customers rate the food as 'poor' is (0.87)^n.

We want to find the smallest value of n for which the probability that at least one person will rate the food as 'poor' is greater than 0.95. In other words, we want to find the smallest value of n for which 1 - (0.87)^n > 0.95.

To solve this equation, we can take the logarithm of both sides. Using the logarithmic property log(1 - x) = -log(x), we can rewrite the equation as -log((0.87)^n) > log(0.05).

Simplifying further, we get n * log(0.87) < log(0.05). Dividing both sides by log(0.87), we obtain n > log(0.05) / log(0.87).

Now, we can plug the values into a calculator to find the smallest value of n.

Using logarithms, the smallest value of n for which the probability that at least one person will rate the food as 'poor' is greater than 0.95 can be obtained by evaluating n > log(0.05) / log(0.87).