The sum of a number times 7 and 28 is at least 24.
To solve this inequality, we can set up an equation. Let's assume the number is represented by the variable "x."
The given information can be expressed as:
7x + 28 ≥ 24
To solve for x, we will isolate it by subtracting 28 from both sides of the inequality:
7x ≥ 24 - 28
7x ≥ -4
Next, we divide both sides of the inequality by 7 to solve for x:
x ≥ -4/7
So, the solution is x is greater than or equal to -4/7.
To solve this problem, we need to set up an inequality.
Let's denote the number as "x".
The sum of the number times 7 and 28 can be written as:
7x + 28
The word "at least" in the question suggests that the sum is greater than or equal to 24. So we can write the inequality as:
7x + 28 ≥ 24
Now, we can solve this inequality:
Subtracting 28 from both sides, we get:
7x ≥ 24 - 28
Simplifying further:
7x ≥ -4
Finally, we divide both sides by 7 to isolate the variable:
x ≥ -4/7
Therefore, the solution to the inequality is x is greater than or equal to -4/7.