In a primary school 70% of the boys and 55% of girls can ride a bicycle if a boy and a girl are chosen at random what is the probability that both of them can ride a bicycle. That neither of them can ride a bicycle?

27/200

p(both ride) = 0.70 * 0.55

p(neither ride) = (1 - 0.70) * (1 - 0.55)

help na which one na savino. you are high in the stomach and mad in the belly

Do we multiply 0.70 and 0.55

Savino

To determine the probability that both a boy and a girl can ride a bicycle, we need to multiply the probabilities of each event happening. Here's how to calculate it:

1. Calculate the probability that a boy can ride a bicycle: 70%
2. Calculate the probability that a girl can ride a bicycle: 55%
3. Multiply these two probabilities: 0.70 x 0.55 = 0.385
4. The probability that both a boy and a girl can ride a bicycle is 0.385, or 38.5%.

Now, let's calculate the probability that neither the boy nor the girl can ride a bicycle. Since this is the opposite event of both of them being able to ride:

1. Calculate the probability that both the boy and the girl can ride a bicycle: 0.385
2. Subtract this probability from 1 to get the probability of the opposite event: 1 - 0.385 = 0.615
3. The probability that neither the boy nor the girl can ride a bicycle is 0.615, or 61.5%.

So, the probability that both a boy and a girl can ride a bicycle is 38.5%, and the probability that neither of them can ride a bicycle is 61.5%.

0,70+0,55

student

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