Calculate the linear expansivity of brass of length of 120m that assume a new length of 120.05m when heated through a temperature of 100°
change in length / length = k * change in temp
0.05 / 120 = k * 100
k = 0.0005/10 = 5 * 10^-4 / 10 = 5 * 10^-5
whoops, division wrong
0.05 / 120 = k * 100
= 0.05/12000 = 4.17 * 10^-6
To calculate the linear expansivity of brass, we can use the formula:
ΔL = α * L * ΔT
Where:
ΔL is the change in length (in this case, from 120m to 120.05m)
α is the linear expansivity of brass
L is the original length (120m)
ΔT is the change in temperature (100°C)
Rearranging the formula to solve for α, we have:
α = ΔL / (L * ΔT)
Substituting the given values:
α = (120.05m - 120m) / (120m * 100°C)
Simplifying this equation gives us:
α = 0.05m / (120m * 100°C)
Now we can calculate the linear expansivity of brass:
α = 0.05 / (120 * 100) [1/°C]
α = 0.05 / 12000 [1/°C]
α = 4.167 x 10^-6 [1/°C]
Therefore, the linear expansivity of brass in this case is 4.167 x 10^-6 per degree Celsius.