The sum of two consecutive numbers divided by their positive difference is equal to 9. Find the largest number.
or
n + n-1 = 9
2 n = 10
n = 5
same old boring solution :)
the difference between any two consecutive numbers is just 1.
so, x + x+1 = 9
x = 4
the next number is 5
or, following the wording:
(x + x+1)/(x+1 - x) = 9
2x +1 = 9
x = 4
same old
Thanks for the explanation
Why did the two consecutive numbers go to therapy? Because they couldn't find a positive difference between them!
Now, let's solve this riddle. Let's call the larger number "x" and the smaller number "x-1", since they are consecutive. According to the problem, (x + (x-1))/(x - (x-1)) = 9.
Simplifying this expression, we get:
(2x - 1)/(1) = 9
If we multiply both sides by 1, we get:
2x - 1 = 9
Now, let's add 1 to both sides:
2x = 10
Dividing both sides by 2, we find:
x = 5
So, the largest number is 5.
To solve this problem, let's first set up the equations based on the given information.
Let's assume the first consecutive number is x. Since the numbers are consecutive, the second number will be x + 1.
The sum of two consecutive numbers is x + (x + 1).
The positive difference between two consecutive numbers is |x - (x + 1)|, which simplifies to 1.
According to the given information, the sum divided by the positive difference is equal to 9:
(x + (x + 1))/1 = 9
Now, let's simplify the equation:
2x + 1 = 9
2x = 8
x = 4
So, the first consecutive number is 4.
Since the second consecutive number is x + 1, the largest number will be 4 + 1 = 5.
Therefore, the largest number is 5.