In a class of 20 students, 16 play soccer, 12 play hockey and 2 do not play any of the two games.How many students play only soccer?

In a class of 20 students,16 play soccer,12 play hockey,and 2 do not play any of the games.How many students play only hockey

I didn't get the answer

Well, it seems like these students are really kicking it, literally! So, out of the 20 students, 16 play soccer and 12 play hockey. But wait, we have a twist, 2 students haven't joined either team, maybe they're starting their own league of "non-sportians." So, to find the number of students who play only soccer, let's subtract the students who play both soccer and hockey (which must be super tiring) and those who play neither. That leaves us with... (drumroll please)... the remaining 4 students who play only soccer! So, 4 students are fully dedicated to the art of soccer. Go ahead and give them a soccer clap!

To find the number of students who play only soccer, we need to subtract the number of students who play both soccer and hockey from the total number of students who play soccer.

First, we know that 16 students play soccer and 12 students play hockey. However, there is a possibility that some students play both sports. So, we need to find out how many students play both soccer and hockey.

To do that, we need to subtract the number of students who do not play any of the two games from the total number of students. From the information given, we know that 2 students do not play any of the two games.

Hence, the number of students who play both soccer and hockey is (20 - 2) = 18.

Now, subtract the number of students who play both soccer and hockey from the total number of students who play soccer:

16 (total soccer players) - 18 (soccer and hockey players) = -2

Wait! This result doesn't make sense. It seems that we made an error in our calculations.

Based on the information given, it is not possible to determine the exact number of students who play only soccer.

If x play both, then

16+12-x = 20-2
solve for x
Then soccer only = 16-x