A cylindrical tin full of engine oil has a diameter of 12cm and a height of 14cm. The oil is poured into a rectangular tin 16cm long and 11cm wide. What is the depth of the oil in the tin?

the volumes are equal

π * (12/2)^2 * 14 = d * 16 * 11

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The volume doesn't change, so if the oil has depth h, then

16*11*h = π*6^2*14

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