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Math

Point R(3,7) and point S(−1,−4) are located within the coordinate plane.

What is the distance between the two points?

137
194−−−√
13−−√
137−−−√
could someone help me understand please

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  1. X = -1-3 = -4.
    Y = -4 -7 = -11.
    d^2 = X^2+Y^2 = (-4)^2 + (-11)^2 = 137.
    d =

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  2. the points are 4-units apart in the x-direction
    ... and 11-units apart in the y-direction

    the axes are at right angles to each other
    ... so you can use Pythagoras to find the distance

    (total distance)^2 = (x-distance)^2 + (y-distance)^2

    d^2 = 4^2 + 11^2 = 16 + 121

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  3. its 137−−−√ I just finished the exam.

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