The lunch special at Jimmy John’s costs $5.60. The math club has $50.40 in its treasury. How many lunch specials can the club buy? Write and solve an inequality. Show your work

number of lunches ≤ 50.4/5.6

x = 50.40 / 5.60 = 9

To find out how many lunch specials the math club can buy, we can set up an inequality.

Let's assume the math club can buy 'x' lunch specials.

We know that the cost of one lunch special is $5.60, so 'x' lunch specials would cost 5.60 * x dollars.

Since the math club has $50.40 in its treasury, the amount it can spend on lunch specials is $50.40.

Therefore, the inequality can be written as:

5.60 * x ≤ 50.40

To solve this inequality for 'x', divide both sides of the inequality by 5.6:

x ≤ 50.40 ÷ 5.60

Simplifying the right side gives:

x ≤ 9

So, the math club can buy a maximum of 9 lunch specials.