two solutions A and B are provided to you. A is a solution of M/50 potassium permanganate. B is a solution of hydrated sample of oxalic acid per 100 ml. calculate the percentage of water of crystallization in hydrated sample of oxalic acid.
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neha
Better hope Chemistry teacher drops in.
Damon
first, fix the missing information in the question...
To calculate the percentage of water of crystallization in the hydrated sample of oxalic acid, we need to determine the amount of water present in the sample and express it as a percentage of the total weight.
Here's how you can do it:
1. Determine the molar mass of oxalic acid (C2H2O4):
Carbon (C) has a molar mass of 12.01 g/mol,
Hydrogen (H) has a molar mass of 1.008 g/mol,
Oxygen (O) has a molar mass of 16.00 g/mol.
Therefore, the molar mass of oxalic acid is:
(2 * 12.01 g/mol) + (2 * 1.008 g/mol) + (4 * 16.00 g/mol) = 90.04 g/mol.
2. Convert the mass of the hydrated sample provided to moles of oxalic acid:
Divide the given mass of the hydrated sample by the molar mass of oxalic acid to get the number of moles.
3. Determine the molar mass of water (H2O):
Hydrogen (H) has a molar mass of 1.008 g/mol,
Oxygen (O) has a molar mass of 16.00 g/mol.
Therefore, the molar mass of water is:
(2 * 1.008 g/mol) + (1 * 16.00 g/mol) = 18.02 g/mol.
4. Determine the molar mass of the hydrated sample:
Subtract the molar mass of oxalic acid from the molar mass of the hydrated sample to get the molar mass of water present in one mole of the sample.
5. Calculate the percentage of water of crystallization:
Divide the molar mass of water by the molar mass of the hydrated sample and multiply by 100 to get the percentage.
Let's calculate an example using the given information:
Suppose we have a hydrated sample of oxalic acid weighing 5.00 g.
1. Molar mass of oxalic acid: 90.04 g/mol
2. Moles of oxalic acid in the sample: 5.00 g / 90.04 g/mol = 0.0555 mol (approx.)
3. Molar mass of water (H2O): 18.02 g/mol
4. Molar mass of hydrated sample: (0.0555 mol * 18.02 g/mol) = 1.00 g (approx.)
5. Percentage of water of crystallization: (18.02 g/mol / 1.00 g) * 100 = 1802% (approx.)
Therefore, the calculated percentage of water of crystallization in the hydrated sample of oxalic acid is approximately 1802%.