# Mathematics

An aeroplane leaves an airport A and flies on a bearing 035°for 1.5 hours at 600km/hr to airport B It then flies on a bearing 130° for 1.5hours at 400km per hour to an airport C calculate the distance from C to A and the bearing of C from A with the diagram of the bearing

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1. distance AB = (1.5)(600) km or 900 km
distance BC = 1.5(400) km or 600 km
I assume you drew your diagram correctly.
So now you have triangle ABC with AB = 900, BC = 600 and angle B = 75°

Use the cosine law to find AC

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Reiny
2. AB = 900km[35o].
BC = 600km[130o].
AC = ?

AC = AB + BC. = 900[35o] + 600[130o]..
AC = (900*sin35+600*sin130) + (900*cos35+600*cos130)I,
AC = 975.8 + 351.6i = 1037km[70.2o].
Bearing of 70.2 Degrees.

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3. Teach me I wan the particular answer of this question plss

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