Mathematics

An aeroplane leaves an airport A and flies on a bearing 035°for 1.5 hours at 600km/hr to airport B It then flies on a bearing 130° for 1.5hours at 400km per hour to an airport C calculate the distance from C to A and the bearing of C from A with the diagram of the bearing

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  1. distance AB = (1.5)(600) km or 900 km
    distance BC = 1.5(400) km or 600 km
    I assume you drew your diagram correctly.
    So now you have triangle ABC with AB = 900, BC = 600 and angle B = 75°

    Use the cosine law to find AC

    Let me know what you did, and what your answer is.

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    Reiny
  2. AB = 900km[35o].
    BC = 600km[130o].
    AC = ?

    AC = AB + BC. = 900[35o] + 600[130o]..
    AC = (900*sin35+600*sin130) + (900*cos35+600*cos130)I,
    AC = 975.8 + 351.6i = 1037km[70.2o].
    Bearing of 70.2 Degrees.

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  3. Teach me I wan the particular answer of this question plss

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