A boy spent 3/8 of his pocket money and GHC 15 left. How much did he have?
I do not understand
To find out how much money the boy originally had, we can use a simple equation.
Let's assume the boy's original amount of pocket money is "P".
According to the information given, he spent 3/8 of his pocket money, which means he has (1 - 3/8) = 5/8 of his pocket money left.
We also know that he has GHC 15 left, so we can set up the following equation:
(5/8) * P = 15
To solve for P, we can multiply both sides of the equation by 8/5:
P = 15 * (8/5)
P = 24
Therefore, the boy originally had GHC 24 as his pocket money.
To find out how much pocket money the boy had initially, we can use algebra.
Let's assume the pocket money the boy had initially is "x".
We know that he spent 3/8 of his pocket money, which is given by (3/8) * x.
We also know that he had GHC 15 left, so his remaining pocket money is given by x - (3/8) * x = (5/8) * x = GHC 15.
To find the value of "x", we can multiply both sides of the equation by 8/5:
(8/5) * [(5/8) * x] = (8/5) * (15)
x = (8/5) * 15
x = 24
Therefore, the boy initially had GHC 24 as his pocket money.
spent 3/8, leaving 5/8. So,
5/8 x = 15
Now just find x.