In ΔCAB, point E is the midpoint of segment AC and point D is the midpoint of segment BC. If the measure of segment AB is 8 units, what is the measure of segment segment ED?
triangle CAB, point E is on segment AC between points A and C and point D is on segment BC between points B and C, creating segment ED
1. 3 units
2. 4 units
3. 5 units
4. 6 units
4 units. I believe
4 Units
To find the measure of segment ED, we need to understand the concept of midpoints and how they divide a line segment.
Given that point E is the midpoint of segment AC and point D is the midpoint of segment BC, we can infer that AE is equal to EC and BD is equal to DC. These properties are true for any midpoint on a line segment.
To find the measure of segment ED, we need to determine the lengths of AE and BD and then add them together.
Since E is the midpoint of AC, the length of AE is half of AC. Given that the measure of segment AB is 8 units, we can deduce that the length of AC is twice that, which is 16 units.
Similarly, since D is the midpoint of BC, the length of BD is half of BC. Knowing that the measure of segment AB is 8 units, we can conclude that the length of BC is also 8 units.
Therefore, the length of BD is half of 8 units, which is 4 units.
Now, to find the measure of segment ED, we add the lengths of AE and BD: AE + BD = 16 units + 4 units = 20 units.
So, the measure of segment ED is 20 units.
None of the options provided match the correct answer, as the measure of segment ED is 20 units.
sing similar triangles, DE = 1/2 (ab)
LOL HIIIIIIIIIIII
its 6